Integrand size = 21, antiderivative size = 217 \[ \int \frac {\sec ^n(e+f x)}{(a+a \sec (e+f x))^2} \, dx=-\frac {2 (2-n) \sec ^{1+n}(e+f x) \sin (e+f x)}{3 a^2 f (1+\sec (e+f x))}-\frac {\sec ^{1+n}(e+f x) \sin (e+f x)}{3 f (a+a \sec (e+f x))^2}-\frac {(3-2 n) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1-n}{2},\frac {3-n}{2},\cos ^2(e+f x)\right ) \sec ^{-1+n}(e+f x) \sin (e+f x)}{3 a^2 f \sqrt {\sin ^2(e+f x)}}+\frac {2 (2-n) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},-\frac {n}{2},\frac {2-n}{2},\cos ^2(e+f x)\right ) \sec ^n(e+f x) \sin (e+f x)}{3 a^2 f \sqrt {\sin ^2(e+f x)}} \]
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Time = 0.38 (sec) , antiderivative size = 217, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.238, Rules used = {3902, 4105, 3872, 3857, 2722} \[ \int \frac {\sec ^n(e+f x)}{(a+a \sec (e+f x))^2} \, dx=-\frac {(3-2 n) \sin (e+f x) \sec ^{n-1}(e+f x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1-n}{2},\frac {3-n}{2},\cos ^2(e+f x)\right )}{3 a^2 f \sqrt {\sin ^2(e+f x)}}+\frac {2 (2-n) \sin (e+f x) \sec ^n(e+f x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},-\frac {n}{2},\frac {2-n}{2},\cos ^2(e+f x)\right )}{3 a^2 f \sqrt {\sin ^2(e+f x)}}-\frac {2 (2-n) \sin (e+f x) \sec ^{n+1}(e+f x)}{3 a^2 f (\sec (e+f x)+1)}-\frac {\sin (e+f x) \sec ^{n+1}(e+f x)}{3 f (a \sec (e+f x)+a)^2} \]
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Rule 2722
Rule 3857
Rule 3872
Rule 3902
Rule 4105
Rubi steps \begin{align*} \text {integral}& = -\frac {\sec ^{1+n}(e+f x) \sin (e+f x)}{3 f (a+a \sec (e+f x))^2}-\frac {\int \frac {\sec ^n(e+f x) (a (-3+n)-a (-1+n) \sec (e+f x))}{a+a \sec (e+f x)} \, dx}{3 a^2} \\ & = -\frac {2 (2-n) \sec ^{1+n}(e+f x) \sin (e+f x)}{3 a^2 f (1+\sec (e+f x))}-\frac {\sec ^{1+n}(e+f x) \sin (e+f x)}{3 f (a+a \sec (e+f x))^2}-\frac {\int \sec ^n(e+f x) \left (-a^2 (3-2 n) (1-n)-2 a^2 (2-n) n \sec (e+f x)\right ) \, dx}{3 a^4} \\ & = -\frac {2 (2-n) \sec ^{1+n}(e+f x) \sin (e+f x)}{3 a^2 f (1+\sec (e+f x))}-\frac {\sec ^{1+n}(e+f x) \sin (e+f x)}{3 f (a+a \sec (e+f x))^2}+\frac {((3-2 n) (1-n)) \int \sec ^n(e+f x) \, dx}{3 a^2}+\frac {(2 (2-n) n) \int \sec ^{1+n}(e+f x) \, dx}{3 a^2} \\ & = -\frac {2 (2-n) \sec ^{1+n}(e+f x) \sin (e+f x)}{3 a^2 f (1+\sec (e+f x))}-\frac {\sec ^{1+n}(e+f x) \sin (e+f x)}{3 f (a+a \sec (e+f x))^2}+\frac {\left ((3-2 n) (1-n) \cos ^n(e+f x) \sec ^n(e+f x)\right ) \int \cos ^{-n}(e+f x) \, dx}{3 a^2}+\frac {\left (2 (2-n) n \cos ^n(e+f x) \sec ^n(e+f x)\right ) \int \cos ^{-1-n}(e+f x) \, dx}{3 a^2} \\ & = -\frac {2 (2-n) \sec ^{1+n}(e+f x) \sin (e+f x)}{3 a^2 f (1+\sec (e+f x))}-\frac {\sec ^{1+n}(e+f x) \sin (e+f x)}{3 f (a+a \sec (e+f x))^2}-\frac {(3-2 n) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1-n}{2},\frac {3-n}{2},\cos ^2(e+f x)\right ) \sec ^{-1+n}(e+f x) \sin (e+f x)}{3 a^2 f \sqrt {\sin ^2(e+f x)}}+\frac {2 (2-n) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},-\frac {n}{2},\frac {2-n}{2},\cos ^2(e+f x)\right ) \sec ^n(e+f x) \sin (e+f x)}{3 a^2 f \sqrt {\sin ^2(e+f x)}} \\ \end{align*}
Time = 1.83 (sec) , antiderivative size = 192, normalized size of antiderivative = 0.88 \[ \int \frac {\sec ^n(e+f x)}{(a+a \sec (e+f x))^2} \, dx=\frac {\csc (e+f x) \sec ^n(e+f x) \left (-n (1+n) \sin (e+f x) \tan (e+f x)+(1+\sec (e+f x)) \left (2 (-2+n) n (1+n) \sin (e+f x) \tan (e+f x)+\left ((-1+n) (1+n) (-3+2 n) \cos (e+f x) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {n}{2},\frac {2+n}{2},\sec ^2(e+f x)\right )-2 (-2+n) n^2 \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {1+n}{2},\frac {3+n}{2},\sec ^2(e+f x)\right )\right ) (1+\sec (e+f x)) \sqrt {-\tan ^2(e+f x)}\right )\right )}{3 a^2 f n (1+n) (1+\sec (e+f x))^2} \]
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\[\int \frac {\sec \left (f x +e \right )^{n}}{\left (a +a \sec \left (f x +e \right )\right )^{2}}d x\]
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\[ \int \frac {\sec ^n(e+f x)}{(a+a \sec (e+f x))^2} \, dx=\int { \frac {\sec \left (f x + e\right )^{n}}{{\left (a \sec \left (f x + e\right ) + a\right )}^{2}} \,d x } \]
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\[ \int \frac {\sec ^n(e+f x)}{(a+a \sec (e+f x))^2} \, dx=\frac {\int \frac {\sec ^{n}{\left (e + f x \right )}}{\sec ^{2}{\left (e + f x \right )} + 2 \sec {\left (e + f x \right )} + 1}\, dx}{a^{2}} \]
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\[ \int \frac {\sec ^n(e+f x)}{(a+a \sec (e+f x))^2} \, dx=\int { \frac {\sec \left (f x + e\right )^{n}}{{\left (a \sec \left (f x + e\right ) + a\right )}^{2}} \,d x } \]
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\[ \int \frac {\sec ^n(e+f x)}{(a+a \sec (e+f x))^2} \, dx=\int { \frac {\sec \left (f x + e\right )^{n}}{{\left (a \sec \left (f x + e\right ) + a\right )}^{2}} \,d x } \]
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Timed out. \[ \int \frac {\sec ^n(e+f x)}{(a+a \sec (e+f x))^2} \, dx=\int \frac {{\left (\frac {1}{\cos \left (e+f\,x\right )}\right )}^n}{{\left (a+\frac {a}{\cos \left (e+f\,x\right )}\right )}^2} \,d x \]
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